1+x+x^2+x^3+...+x^n Formula Proof

3 min read Jun 15, 2024
1+x+x^2+x^3+...+x^n Formula Proof

The Formula for 1 + x + x^2 + x^3 + ... + x^n

The formula for the sum of a geometric series, 1 + x + x^2 + x^3 + ... + x^n, is a fundamental concept in mathematics. In this article, we will prove the formula for this sum.

The Formula

The formula for the sum of a geometric series is:

1 + x + x^2 + x^3 + ... + x^n = (x^(n+1) - 1) / (x - 1)

Proof

To prove this formula, we will use the method of mathematical induction.

Base Case

First, we will show that the formula is true for n = 0.

1 + x^0 = 1 = (x^(0+1) - 1) / (x - 1) = (x - 1) / (x - 1) = 1

This shows that the formula is true for n = 0.

Inductive Step

Now, we will assume that the formula is true for n = k. That is, we assume that:

1 + x + x^2 + x^3 + ... + x^k = (x^(k+1) - 1) / (x - 1)

We will show that if the formula is true for n = k, then it is also true for n = k + 1.

1 + x + x^2 + x^3 + ... + x^(k+1) = (1 + x + x^2 + x^3 + ... + x^k) + x^(k+1)

Using the assumption that the formula is true for n = k, we can rewrite the right-hand side as:

= ((x^(k+1) - 1) / (x - 1)) + x^(k+1)

= (x^(k+1) - 1 + x^(k+1) - x^(k+1) + 1) / (x - 1)

= (x^(k+2) - 1) / (x - 1)

This shows that the formula is true for n = k + 1.

Conclusion

By mathematical induction, we have shown that the formula:

1 + x + x^2 + x^3 + ... + x^n = (x^(n+1) - 1) / (x - 1)

is true for all positive integers n.

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